Small C++ problem, please help?

Write the definition of a function powerTo , which receives two parameters. The first is a double and the second is an int .


The function returns a double .





If the second parameter is negative, the function returns 0. Otherwise, it returns the value of the first parameter raised to the power of the second.





I cannot do this problem. Here's what I have:


double powerTo(double base, int power)


{


int n;


if (power %26lt; 0)


return 0;





for (double k = 1; k %26lt; n; k++)


k = base *= power;


return k;


}





This is the last problem I have to do, and it has been months and I still cannot do it!


Can anyone answer this question, using C++ and not C please

Small C++ problem, please help?
following answer is given by fred:








double powerTo(double base, int power)


{


　　double answer=1;





　　for(int i=0;i%26lt;power;i++)


　　　　answer*=base;





　　return answer;


}





This is perfectly alright logically, but would not server your purpose. i.e. it would not return a 0 for negative second parameter. You can modify it by introducing a statement in Fred's code as the first statement of the function:





if (power%26lt;0) return 0;





thus the function becomes:





double powerTo(double base, int power)


{


　　if (power%26lt;0) return 0.0;


double answer=1.0;





　　for(int i=0;i%26lt;power;i++)


　　　　answer*=base;





　　return answer;


}
Reply:Here is the correct function.





double powerTo(double base, int power)


{


　　double answer=1;





　　for(int i=0;i%26lt;power;i++)


　　　　answer*=base;





　　return answer;


}








How does this work?





Le'ts look at this example.





2^5





2^5 is 1 * 2 * 2 * 2 * 2 * 2. Right?





That's why the local variable "Answer" is 1 by default.





We can multiply the base as many time as power states to 1.





So you iterate from 0 to power - 1 using for loop (it means i starts from 0 and run till it reaches power) and multiply "base" to 1.





If you don't understand my answer, please add details to your questions.





*ADDED


I didn't see the answer%26lt;0 part. So the code will be...





double powerTo(double base, int power)


{


　　double answer=(power %26gt;=0 ? 1 : 0);





　　for(int i=0;i%26lt;power;i++)


　　　　answer*=base;





　　return answer;


}