In a Young's double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to the screen is 2.5 m, find the spacing between the first-order and second-order bright fringes for light with wavelength of 600 nm.
a. 3.0 cm
b. 1.5 cm
c. 4.5 cm
d. 6.0 cm
Double Slit Experiment!?!?
delta y = y2 - y1 = 2 lamba L / d - 1 lamba x L / d = lamba x L /d
y = lambda x L / d
y = 600 x 10^-9 x 2.5m / 0.050 x 10^-3 m
y = 0.03m
= 3cm
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