Monday, May 24, 2010

Help overloading assignment operator in C++?

Trying to overload the assignment operator in C++





Point%26amp; Point::operator=(const Point%26amp; p)


{


if(this != %26amp;p)


{


delete [] label; //Deletes label


label = new char(strlen (*(p.label)));


strcpy(label, (*(p.label)));


x = (*(p.x)); //Copies x.


y = (*(p.y)); //Copies y


}


return *this; //Returns *this.


}





h:\point\point\point\point.cpp(64) : error C2664: 'strlen' : cannot convert parameter 1 from 'char' to 'const char *'


Conversion from integral type to pointer type requires reinterpret_cast, C-style cast or function-style cast


h:\point\point\point\point.cpp(64) : fatal error C1903: unable to recover from previous error(s); stopping compilation





With line 64 commented out:





h:\point\point\point\point.cpp(65) : error C2664: 'strcpy' : cannot convert parameter 2 from 'char' to 'const char *'


Conversion from integral type to pointer type requires reinterpret_cast, C-style cast or function-style cast


h:\point\point\point\point.cpp(66) : error C2440: '=' : cannot convert from 'double' to 'double *'


h:\point\point\point\point.cpp(67) : error C2440: '=' : cannot convert from 'double' to 'double *'

Help overloading assignment operator in C++?
label = new char(strlen (*(p.label)));


strcpy(label, (*(p.label)));


x = (*(p.x)); //Copies x.


y = (*(p.y)); //Copies y





The code above replace with





label = new char(strlen ((p.label)));


strcpy(label, ((p.label)));


x = p.x; //Copies x.


y = p.y; //Copies y
Reply:????
Reply:Ok, The line


Point%26amp; Point::operator = (const Point%26amp; p)


This means that your argument to the function is passed by reference, and returns a reference.


A reference argument is used like a regular argument, no special treatment required.


I believe the assignment operator is redefined as


Point%26amp; Point::operator = (const Point%26amp; p)


The complete function would be


Point%26amp; Point::operator = (const Point%26amp; p)


{


if (this == %26amp;p)


return *this;


char *temp;


double dx, dy;


temp = new char[strlen(p.label) + 1];


strcpy(temp, p.label);


dx = p.x;


dy = p.y;


x = dx;


y = dy;


delete label;


label = new char[strlen(temp) + 1];


strcpy(label, temp);


delete temp;


return *this;


}

hawthorn

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