BE IN DEGREES CELSIUS? ANSWER IN UNITS OF °C
THE PRESSURE ON A GAS AT -87°c IS DOUBLED BUT ITS VOLUME IS HELD CONSTANT.WHAT WILL THE FINAL TEMP ....?
The initial pressure divided by the initial temperature is equal to the final pressure divided by the final temperature. Pressure must be in units of atmospheres and temperature in Kelvins, so add 273 to your value of -87 degrees.
P / 186 K = 2P / T
If you double the pressure, to keep it equal to the first half of the equation, you must also double the temperature.
To stick with an easy example, say you have 2 / 10. If you double the 2 to make 4, you must also double the 10 to 20 in order to keep the equation equal.
2 / 10 = 4 / 20.
Your temperature in this case would be around 372 K, or about 99 degrees Celsius.
Hope this helps!
Reply:In this question, you must use Charles' law, which says:
P1 / T1 = P2 / T2
Volume being held constant is important because otherwise Boyle's law would go into effect (P1V1 = P2V2). By the way, P is pressure, V is volume, T is temperature.
So, first of all, in these laws that involve temperature, you only use temperature in Kelvin. So, -87 degrees Celsius + 273 = 186 Kelvin.
Now, if pressure is doubled we can say that P2 = 2P1. So, our equation is:
P1 / 186K = 2P1 / T2.
So, T2 = 2P1 times 186K / P1.
Therefore, we get T2 to equal 372 K since the 2P1 / P1 = 2.
Now we need to convert back to degrees Celsius.
X + 273 = 372 Kelvin.
X = 99 degrees Celsius
Final Answer: 99 degrees Celsius
Reply:You can use the combined gas law to solve this problem.
P1V1 / T1 = P2V2 / T2
Since the V is held constant, the equation becomes
P1 / T1 = P2 / T2 (Must use T in kelvins!)
Rearranging the equation,
T2 / T1 = P2 / P1
If P2 is 2 x P1, then
T2 / T1 = 2P1 / P1 = 2
The final temperature, T2 is therefore doubled compared to T1
T1 = (-87 + 273 ) = 185 K
T2 is 2 x T1 = 2 x 185 K = 370 K
C = 370 - 273 = 97 C
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