temperatures of the source is?
An engine has an efficiency of 1/6.when the temperature of sink is redused by 62*c,itsefficiency is doubled.te
Ok, is it a Carnot machine ?
Because if it's, then :
efficiency = n = 1 - T2 / T1
1/6 = 1 - T2 / T1
T2 / T1 = 5 / 6
T2 = 5k
T1 = 6k
when T2, decreased (62+273) K
1/3 = 1 - (T2 - 335) / x
T2 = 5k
5k - 335 / 6k - x = 2/3
let's set k = 1
5 - 335 / 6-x = 2/3
30 - 5x - 335 = 6-x*2/3
-305 - 5x = 12 - 2x / 3
-915 - 15x = 12 - 2x
-927 = 13x
x = -71.3
So, the Temperature of the source has decreased in 71.3
Hope that helps
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment